1295. Find Numbers with Even Number of Digits

Problem

Tags: Array

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

Constraints:

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

Code

JS

// 1295. Find Numbers with Even Number of Digits (7/14/53411)
// Runtime: 76 ms (59.59%) Memory: 39.39 MB (94.77%) 

/**
 * @param {number[]} nums
 * @return {number}
 */
var findNumbers = function(nums) {
    let count = 0;
    
    for(let i = 0; i < nums.length; i++) {
        if(String(nums[i]).length % 2 === 0) count++;
    }
    
    return count;
};