189. Rotate Array
Problem
Tags: Array
, Math
, Two Pointers
Given an array, rotate the array to the right by k
steps, where k
is non-negative.
Example 1:
Input: nums = [1,2,3,4,5,6,7], k = 3
Output: [5,6,7,1,2,3,4]
Explanation:
rotate 1 steps to the right: [7,1,2,3,4,5,6]
rotate 2 steps to the right: [6,7,1,2,3,4,5]
rotate 3 steps to the right: [5,6,7,1,2,3,4]
Example 2:
Input: nums = [-1,-100,3,99], k = 2
Output: [3,99,-1,-100]
Explanation:
rotate 1 steps to the right: [99,-1,-100,3]
rotate 2 steps to the right: [3,99,-1,-100]
Constraints:
1 <= nums.length <= 10^5
-2^31 <= nums[i] <= 2^31 - 1
0 <= k <= 10^5
Follow up:
- Try to come up with as many solutions as you can. There are at least three different ways to solve this problem.
- Could you do it in-place with
O(1)
extra space?
Code
JS
// 189. Rotate Array (3/23/53714)
// Runtime: 104 ms (71.87%) Memory: 50.08 MB (94.87%)
/**
* @param {number[]} nums
* @param {number} k
* @return {void} Do not return anything, modify nums in-place instead.
*/
function rotate(nums, k) {
const steps = k % nums.length;
if (steps === 0) return;
reverse(0, nums.length - 1);
reverse(0, steps - 1);
reverse(steps, nums.length - 1);
function reverse(start, end) {
while (start < end) {
[nums[start], nums[end]] = [nums[end], nums[start]];
start++;
end--;
}
}
}