203. Remove Linked List Elements
Problem
Tags: Linked List
, Recursion
Given the head
of a linked list and an integer val
, remove all the nodes of the linked list that has Node.val == val
, and return the new head.
Example 1:
Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
Example 2:
Input: head = [], val = 1
Output: []
Example 3:
Input: head = [7,7,7,7], val = 7
Output: []
Constraints:
- The number of nodes in the list is in the range
[0, 10^4]
. 1 <= Node.val <= 50
0 <= val <= 50
Code
JS
// 203. Remove Linked List Elements (11/24/53727)
// Runtime: 126 ms (17.28%) Memory: 43.35 MB (93.75%)
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode} head
* @param {number} val
* @return {ListNode}
*/
function removeElements(head, val) {
let hair = new ListNode(undefined, head);
let node = hair;
while(node.next) {
if(node.next.val === val) {
if(node.next.next) node.next = node.next.next;
else node.next = null;
} else node = node.next;
}
return hair.next;
};