231. Power of Two
Problem
Tags: Math
, Bit Manipulation
, Recursion
Given an integer n
, return true
if it is a power of two. Otherwise, return false
.
An integer n
is a power of two, if there exists an integer x
such that n == 2^x
.
Example 1:
Input: n = 1
Output: true
Explanation: 20 = 1
Example 2:
Input: n = 16
Output: true
Explanation: 24 = 16
Example 3:
Input: n = 3
Output: false
Constraints:
-2^31 <= n <= 2^31 - 1
Follow up: Could you solve it without loops/recursion?
Code
JS
// 231. Power of Two (6/3/53941)
// Runtime: 80 ms (68.60%) Memory: 40.46 MB (94.98%)
/**
* @param {number} n
* @return {boolean}
*/
function isPowerOfTwo(n) {
return n > 0 && !(n & (n - 1));
}