94. Binary Tree Inorder Traversal

Problem

Tags: Stack, Tree, Depth-First Search, Binary Tree

Given the root of a binary tree, return the inorder traversal of its nodes' values.

Example 1:

Input: root = [1,null,2,3]
Output: [1,3,2]

Example 2:

Input: root = []
Output: []

Example 3:

Input: root = [1]
Output: [1]

Constraints:

• The number of nodes in the tree is in the range [0, 100].
• -100 <= Node.val <= 100

Follow up: Recursive solution is trivial, could you do it iteratively?

Code

JS

// 94. Binary Tree Inorder Traversal (7/3/53737)
// Runtime: 68 ms (65.93%) Memory: 38.96 MB (92.84%) 

/**
 * Definition for a binary tree node.
 * function TreeNode(val, left, right) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.left = (left===undefined ? null : left)
 *     this.right = (right===undefined ? null : right)
 * }
 */
/**
 * @param {TreeNode} root
 * @return {number[]}
 */
function inorderTraversal(root) {
    const result = [];
    const stack = [];
    let node = root;
    while (node || stack.length) {
        while (node) {
            stack.push(node);
            node = node.left;
        }
        node = stack.pop();
        result.push(node.val);
        node = node.right;
    }
    return result;
}